Solve the Physics Problem: Astronaut Drops Camera on Moon

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An astronaut drops a camera from a 14.7 m cliff on the Moon, where it falls for 4.3 seconds. To solve for the distance fallen, the gravitational acceleration on the Moon must first be calculated, which is approximately 1.6256 m/s². Using the kinematic equations, particularly the one for displacement, the initial speed is zero, and the final speed after 2.2 seconds is 3.3 m/s. The calculations involve determining the displacement using the time and acceleration values. The final position can then be found by applying the formula for displacement, taking into account the initial height of the cliff.
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During a walk on the Moon, an astronaut accidentally drops his camera over a 14.7 m cliff. It leaves his hands with zero speed, and after 2.2 s it has attained a velocity of 3.3 m/s downward. How far has the camera fallen after 4.3 s?

I am so lost! I have no idea what to do! I would appreciate any help!
 
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First you have to calculate (or search) the gravity acceleration on the Moon:

g = G.M/R^2 (G: gravitational constant, M, R are the mass and radius of the Moon)

Then everything is straight forward.
 
then would i just multiply that answer by 4.3 for the time?
 
pixel01 said:
First you have to calculate (or search) the gravity acceleration on the Moon:

g = G.M/R^2 (G: gravitational constant, M, R are the mass and radius of the Moon)

Then everything is straight forward.

With the information he was given, the following formula is better:

http://en.wikipedia.org/wiki/Torricelli's_equation

Vy^2 = Vy0^2 + 2aD

Where: Vy is the final speed, Vy0 is the initial speed, a is the acceleration, D is displacement. a is the only unknown, so this should be fairly simple.
 
I am trying to find how far it has fallen. I assume the final speed is the 3.3m/s stated in the problem and the initial is 0m/s. The acceleration on the moon that I figured out from this equation was 1.6256. So should I solve for the displacement? I am so frustrated. I have been working on this since 6 o'clock and I only have half the assignment done.
 
Woops, I'm sorry, I thought you had the displacement from the first 2.2s...

With the only known information being the variation of speed and time, you should use:

Vy = Vy0 + a.t

Where t is time. With the moon gravity obtained (which must be negative, make sure you get the signs right, and I got -1.5m/s), you have to use another equation:

x = x0 + v0.t + 1/2.a.t^2

Where x0 and x are initial and final position, respectively. You should be able to do this now. Now the exercise asks for the position at 4.3s. Solve for x, and make x0 = 14.7m.
 
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