Water/air trap pressure formula

  • Thread starter Thread starter Calymi
  • Start date Start date
  • Tags Tags
    Formula Pressure
AI Thread Summary
To test a pressure switch set to trigger at 4.4 inches of water without electronics, water is poured into a tube connected to a sealed container. A ruler attached to the container measures the water level to determine when the switch activates. The main concern is understanding the correlation between the water height and the air pressure in the container. Calculations may be needed to relate the water height in the riser to the air pressure, considering the ideal gas law. The discussion emphasizes the importance of accurately measuring the water height to ensure the switch triggers correctly.
Calymi
Messages
2
Reaction score
0
I have been set the problem of finding a method that does not use electronics to test a pressure switch. The switch itself is set to trigger at a pressure of 4.4 inches water (+-0.4). The method needs to be simple without any complex setup needed at the time of testing.

diagram.jpg


The image above is the solution I came up with. This has been accepted by my tutor and cannot be changed. Water will be poured into a tube connected to a sealed container until the increased air pressure triggers the pressure switch. A 2.5mm ruler will be marked/attached to one side of the container to check the level at which the switch triggers.

The issue I'm having is one of correct formulas to demonstrate the model. I am computer science based, not physics, which is making it a little difficult to understand the correct formula to use.

My questions are as follows:
1. When the water reaches the equivalent of 4.4" on the ruler will the subsequent increase in air pressure within the container be equivalnet and therefore trigger the switch at the correct time?

2. If not can somebody possibly briefly explain the correlation between the two pressures and/or point me in the direction of the correct formula?

This is not a graded piece of work. It is simple a problem my tutor has set me to help boost my knowledge in a subject I am lacking experience in.

Thank you.
 
Physics news on Phys.org
You need to measure the height of the water in the riser into which you are pouring the water (i.e., the height above the water surface). Measuring it in the big container won't do you much good, unless you are willing to do some calculations to determine the pressure of the air inside the container, based on the reduced air volume and the ideal gas law.

Chet
 
Thanks for the reply Chet.

I'm happy to do the calculations if they aren't stupidly excessive. How would the meausred water in the riser correlate to the air pressure? I.e. Particular ratio? Overall water + added height of riser water = desired inches?

Apologies if the questions seem stupid, this isn't something that I've done before and I'd rather make sure I understand it correctly than muddle through and get the answer by chance.

Caly
 
Calymi said:
Thanks for the reply Chet.

I'm happy to do the calculations if they aren't stupidly excessive. How would the meausred water in the riser correlate to the air pressure? I.e. Particular ratio? Overall water + added height of riser water = desired inches?

Apologies if the questions seem stupid, this isn't something that I've done before and I'd rather make sure I understand it correctly than muddle through and get the answer by chance.

Caly
Riser water height - tank water height = desired inches
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top