Water Chemistry Cation Determination

AI Thread Summary
The discussion revolves around determining the missing cation in a water sample with specified ion concentrations. The user calculated normalities and found an excess of anions over cations, leading to confusion when converting HCO3- concentrations. Using the correct alkalinity value for HCO3- resulted in identifying the missing ion as Cd+2, aligning with the total dissolved solids and charge balance. The importance of balancing positive and negative charges in the solution is emphasized to resolve discrepancies. Ultimately, the key takeaway is that only one cation will satisfy both the mass and charge requirements in the analysis.
biker.josh07
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I'm having some trouble with this one

A water sample contains the following ions (all in mg/L except HCO3-)

K+=70, Sr+2=20, Ca+2=180, Mg+2=80, HCO3-=230 mg/L as CaCO3-2, SO4-2=164, NO3-=37, Cl-=400, CO3-2=35, and B=?? has a valence number of 2 but the sign is unknown.

TDS(Total Dissolved Solids)=1397 mg/L

Assume the water is balanced, identify the missing ion B as being Fe+2, Ba+2, Cd+2 or HPO4-2.

So I worked out the Equivalent Weights and converted the concentrations to the respective normalities.Then I added up all the positive and negative normalities and found a difference of 3.21meq/L favouring the anions.

My problem is when I work out the mass concentration for the B ion I convert the HCO3- to its mass concentration 280.6 mg/L rather than using its alkalinity of 230 mg/L as CaCO3.However this gives me the wrong answer with a molecular weight of 81.2 which doesn't correspond to anything but I get the right answer if I use 230 and it works out to be Cd+2 because you get a molecular weight of 112.8.so yeah this doesn't make sense.
 
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Try converting your cations and anions into electric charge as well. Think of balancing the moles of positive charge and moles of negative charge. For example, if you have 100 mL solution of potassium chloride of concentration 0.050 meq/L, then you will have 0.005 meq of positive charge and 0.005 meq of negative charge. Do that for all the ions and anions to determine the excess charge in moles, equivalents, meq or whatever.

Only one cation will meet the double requirement of providing both the mass (from the TDS number) and the missing charge to exactly counter the excess charge.
 
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