Wave length of a transverse wave

AI Thread Summary
A transverse wave with a frequency of 25 Hz is discussed, with two points 30 cm apart being out of phase by (5*pi)/3 radians. The relationship between phase and wavelength is highlighted, indicating that the phase difference can be used to determine the wavelength. The discussion also touches on the conditions for two waves to cancel each other out, emphasizing that they must be exactly out of phase. Clarifications are sought regarding the equations provided for the waves, with confusion about their forms and the concept of cancellation at all points in time. Ultimately, the original poster resolves their confusion regarding the wavelength calculation.
ness9660
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1) A transverse wave of frequency 25 Hz propa-
gates down a string. Two points 30 cm apart
are out of phase by (5*pi)/3
What is the wave length of the wave? An-
swer in units of cm.

Im kinda lost here, I am unsure how wave length will relate to the given info. I am sure the phase is part of the relation but I am unsure of how. The best I've been able to figure so far would be converting the frequency to a period, then using v= lambda/T.

I suppose phase is key to solving this problem, but maybe I am unsure of exactly how phase relates?





2) Given two equations Y1 = A / (Bx - Ct)^2 Y2= -A / (Bx + Ct - E)^2
At what time will the two waves exactly cancel everywhere? At what point do the waves always cancel?

Ive been reading in my book about this problem and I am unsure exactly what the case is for two waves to cancel each other out. I would assume they have to be exactly out of phase with each other, so that the peak of one corresponds with the valley of another. Although I am unsure how to meet this condition in the above equations.




Thanks for any help!
 
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-1- There are 2*pi radians in a cycle, right? What part of that is 5*pi/3?

-2- Weird question -- I don't get the equation forms either. Y1 and Y2 don't seem like waves, and how can there be a "time" where the waves cancel everywhere? What's everywhere? All x? All t? Are you sure that you've copied that question correctly? Are there other examples of "waves" in your text that use this equation form? Are there maybe some complex exponentials missing from the equations or something?
 
berkeman said:
-1- There are 2*pi radians in a cycle, right? What part of that is 5*pi/3?

-2- Weird question -- I don't get the equation forms either. Y1 and Y2 don't seem like waves, and how can there be a "time" where the waves cancel everywhere? What's everywhere? All x? All t? Are you sure that you've copied that question correctly? Are there other examples of "waves" in your text that use this equation form? Are there maybe some complex exponentials missing from the equations or something?
For #2, here is the full question:

http://img137.imageshack.us/img137/8669/q229ni.gif As for the first problem, their cycles are out of phase (5pi/3)/2pi = .83333, right? so if the points are 30cm apart, the wavelength is .8333 *30cm?
 
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The two waves cancel each other out at any time t when y1+y2=0
 
daveb said:
The two waves cancel each other out at any time t when y1+y2=0


Thanks, after that it was easy to solve.

Iam still however lost on the first problem. So is it .83333 of a cycle out of phase, but I am still unsure as how to relate this to wavelength?
 
ness9660 said:
Thanks, after that it was easy to solve.

Iam still however lost on the first problem. So is it .83333 of a cycle out of phase, but I am still unsure as how to relate this to wavelength?


Actually I just figured it out, thanks for the help!
 
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