Wave packet: math question. QT(Bohm's book)

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Discussion Overview

The discussion revolves around a mathematical question related to wave packets as presented in David Bohm's "Quantum Theory." Participants are trying to understand the integration of a specific equation involving a light pulse and how it results in a sine function.

Discussion Character

  • Technical explanation, Mathematical reasoning, Homework-related

Main Points Raised

  • One participant expresses confusion about how the integration of the left-hand side (LHS) of the equation leads to a sine function.
  • Another participant requests to see the progress made by the original poster to provide better assistance.
  • A participant suggests that the expression (eik - eik)/2 could be related to producing a sine function on the right-hand side (RHS) of the equation.
  • Another participant emphasizes the importance of examining the bounds of the definite integral in understanding the result.
  • One participant mentions the possibility of needing to refer to their calculus book for further clarification.

Areas of Agreement / Disagreement

The discussion remains unresolved, with participants expressing confusion and seeking clarification without reaching a consensus on the integration process or the resulting sine function.

Contextual Notes

Limitations include potential missing assumptions regarding the integration process and the specific definitions of terms used in the equation.

knockout_artist
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Hello,

In David Bohm,s Quantum Theory, in chapter 3 section 2(motion of pulse of light)
There is this equation, I could not understand how, integrating LHS produced a sin.

Please help.

note:
LHS: k0 +Δk is super script. I did not know how to put it closer to integration sign.

Ex(x)= ∫k0-Δk k0+Δk dkeik(x-x0) = 2 ((sin Δk (x-x0)) / (x-x0)) eik0(x-x0)
 
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knockout_artist said:
There is this equation, I could not understand how, integrating LHS produced a sin.

If you could show us how far you did get, we will be better able to help you.
 
Well.. only thing close enough I could think of was (eik - eik)/2
would make is sin on right hand side.
Then also eik0(x-x0) would also get carried on on the RHS.
 
knockout_artist said:
Well.. only thing close enough I could think of was (eik - eik)/2
would make is sin on right hand side.

Look at the bounds of the definite integral.
 
I think I have to look at my calculus book.
I will post if I still have problem.

Thanks for looking at it.
 

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