- #1
Superdreamer
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Hi I was wondering if someone could tell me if I am heading in the right direction with these Thanks in advance
Q1 In an experiment on standing waves, a string 90 cm long is
attached to the prong of an electrically driven tuning fork that oscillates
perpendicular to the length of the string at a frequency of 60 Hz. The
mass of the string is 0.044 kg. What tension must the string be under if it
is to vibrate in four loops?
I used the formula L=4(λ/2) giving 2λ=L L=1.8m
V=fλ v=108m/s then using the formula v=sq root(T/μ) giving me a tension of 279.936N Is this correct
Q2 Two sinusoidal waves with the same amplitude, frequency and
speed, travel in the same direction along a string and interfere with one
another to produce a resultant wave with a displacement
y = (3.0 x 10-3) sin(20x - 4.0t + 0.6) cos(0.6) m. What is (a) the amplitude
and (b) the wavelength of the waves and (c) the phase difference
between them?
Wave is in the form y'(x,t)=[2ym(cos(tetha/2)sin(Kx-wt+1/2(tetha)tetha/2
y'm=2ymcos1/2tetha
answer 1.13mm is this correct?
k=20 rad/m
w=4 rad/s
λ=2pi/k
=2pirad/20rad/m
=31.4cm
T=2pi/w
=1.57seconds
f=1/t
=0.6366hz
I know this is wrong please lead me in the right direction
Q1 In an experiment on standing waves, a string 90 cm long is
attached to the prong of an electrically driven tuning fork that oscillates
perpendicular to the length of the string at a frequency of 60 Hz. The
mass of the string is 0.044 kg. What tension must the string be under if it
is to vibrate in four loops?
I used the formula L=4(λ/2) giving 2λ=L L=1.8m
V=fλ v=108m/s then using the formula v=sq root(T/μ) giving me a tension of 279.936N Is this correct
Q2 Two sinusoidal waves with the same amplitude, frequency and
speed, travel in the same direction along a string and interfere with one
another to produce a resultant wave with a displacement
y = (3.0 x 10-3) sin(20x - 4.0t + 0.6) cos(0.6) m. What is (a) the amplitude
and (b) the wavelength of the waves and (c) the phase difference
between them?
Wave is in the form y'(x,t)=[2ym(cos(tetha/2)sin(Kx-wt+1/2(tetha)tetha/2
y'm=2ymcos1/2tetha
answer 1.13mm is this correct?
k=20 rad/m
w=4 rad/s
λ=2pi/k
=2pirad/20rad/m
=31.4cm
T=2pi/w
=1.57seconds
f=1/t
=0.6366hz
I know this is wrong please lead me in the right direction