Wave Speed Equation: Solve Homework w/ Max Displacement 0.16m

AI Thread Summary
The wave equation y(x,t)=0.8/{(4x+5t)^2+5} describes a moving pulse with a maximum displacement of 0.16m and a velocity of 1.25m/s towards the negative X-axis. At t=0, the pulse is symmetric about the Y-axis, confirming its shape. The discussion emphasizes the need to graph the function to analyze its behavior over time and determine the position of maximum displacement. The maximum displacement occurs at specific x values, which change over time. Understanding the wave's characteristics requires evaluating its symmetry and displacement at various points.
Hydrous Caperilla
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Homework Statement



y(x,t)=0.8/{(4x+5t)^2+5 }represents a moving pulse,where x and y are in metre and tin second.Then choose the options.

(a)Pulse is moving in positive X axis
(b)In 2 secs,it will travel a displacement of 2.5m
(c)It's maximum displacement is 0.16m
(d)It is a symmetric pulse

Homework Equations

The Attempt at a Solution



So since it is a general transverse wave so it's velocity is 1.25 towards negative X axis.

I can't say about the amplitude unless I know the shape of the pulse so How should I graph this and work out the other options
 
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There is no t in the equation.
 
My mistake...sorry
 
Hydrous Caperilla said:

Homework Statement



y(x,t)=0.8/{(4x+5t)^2+5 }represents a moving pulse,where x and y are in metre and tin second.Then choose the options.

(a)Pulse is moving in positive X axis
(b)In 2 secs,it will travel a displacement of 2.5m
(c)It's maximum displacement is 0.16m
(d)It is a symmetric pulse

Homework Equations

The Attempt at a Solution



So since it is a general transverse wave so it's velocity is 1.25 towards negative X axis.

I can't say about the amplitude unless I know the shape of the pulse so How should I graph this and work out the other options
How does it look at t=0?
 
ehild said:
How does it look at t=0?
At t=0,y is 0.16m
 
Hydrous Caperilla said:
At t=0,y is 0.16m
At ##t=0##, ##y## is a function of ##x##.
 
I got the graph and it looks symmetric to Y axis with y=0.16 m at t=0
 
Hydrous Caperilla said:
I got the graph and it looks symmetric to Y axis with y=0.16 m at t=0
You should calculate the position xmax of the maximum of y (it will be a function of t), and then the value of y(xmax,t). That will tell you what the maximum displacement is. You can then check the symmetry of y around xmax.
 
Hydrous Caperilla said:
I got the graph and it looks symmetric to Y axis with y=0.16 m at t=0

Yes, it is symmetric to the Y axis at t=0. At what x does the function $$ y(x)=\frac{0.8}{(4x)^2+5} $$ have its maximum, and what is the maximum displacement from equilibrium?
At what x is the maximum of y(x,t) at a different time, at t = 2 s, for example?
 
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