Wavefunction boundary condition solve for k

AI Thread Summary
The wave function is defined piecewise, with continuity conditions at x = 0 leading to the equations a = C and -ak = 0. The final expression for k is derived as k = 2πb/a, particularly when considering the case where a is much larger than b. If a is significantly smaller than b, k simplifies to 2πb. The discussion highlights the importance of correctly applying the chain rule in derivatives and the implications of the constants a, b, and c potentially being non-positive or non-real. Overall, the analysis emphasizes the boundary conditions and their influence on determining k.
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Homework Statement



A wave function is given by:
\Psi (x) = a cos(2\pi x) + b sin (2\pi x) for\: x&lt;0 \\<br /> and\\<br /> \Psi (x) = Ce^{-kx} for\: x&gt;0 \\

Determine the constant k in terms of a, b and c using the boundary conditions and discuss the case a >> b.

Homework Equations



Wavefunctions and their first order derivatives are continuous at the boundaries. So at x = 0 they will equal each other.

The Attempt at a Solution



acos (2\pi x) + b sin(2\pi x) = Ce^{-kx}

sin 0 = 0 and cos 0 = 1 and exp 0 = 1 therefore;

a = C \\<br /> <br /> -(2\pi x)asin(2\pi x) + (2\pi x)bcos(2\pi x) = -ake^{-kx}

again sin 0 = 0 cos 0 = 1 exp 0 = 1 and x = 0 therefore;

-ak = 0

Soo pretty sure this is correct so far but not sure on the final step?
 
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Check your expressions for the derivatives of the sine and cosine functions. Did you use the chain rule properly?
 
Ahh forgot to get rid of the x so that would mean k = 2pi*b/a. And for cases where a<<b then it is just 2pi*b?
 
I get a different sign for k. The initial problem statement says to consider the case a >> b.

The question seems a little odd to me. The constants a, b, c need not be positive numbers (or even real for that matter.) Anyway, I guess you could make a conclusion about the size of k under the assumption that |a| >> |b|.
 
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