[Waves] Standing waves problem (possibly )

  • Thread starter hiuting
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  • #1
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Homework Statement


The A-string (440Hz) on a piano is 38.9cm long and is clamped tightly at both ends. If the string is under 667-N tension, what is its mass?


Homework Equations


[tex]\lambda[/tex] = vT
[tex]\mu[/tex] = mass/length
v = [tex]\sqrt{F/\mu}[/tex]


The Attempt at a Solution


I don't really know which equations to use


I don't know if it's right
For fundamental harmonics, L = [tex]\lambda[/tex]/2
so 0.389m = [tex]\lambda[/tex]/2
[tex]\lambda[/tex] = 0.778m
[tex]\lambda[/tex] = vT
0.778 = [tex]\sqrt{F/\mu}[/tex] (1/440Hz)
0.778 = [tex]\sqrt{667/\mu}[/tex] (1/440Hz)
[tex]\mu[/tex] = 0.00569 = mass / 0.389m
mass = 0.0022kg
 
Last edited:

Answers and Replies

  • #2
kuruman
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Your third equation is incorrect. The square root of F/μ is the speed of propagation v, not the wavelength.
 
  • #3
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oh right. correction!
 

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