Weight Density and Mass Density

AI Thread Summary
The discussion revolves around calculating weight density and mass density from measured weight, mass, and volume of objects. The correct units for weight density are confirmed as Newtons per cubic meter and for mass density as kilograms per cubic meter. Participants agree that the calculations appear accurate, but there is a suggestion to double-check them for significant figures. A discrepancy is noted between the calculated weight density and the expected value based on mass and gravitational acceleration. The conversation emphasizes the importance of verifying calculations and understanding the relationship between weight and mass.
GreenEyedGal3
Messages
7
Reaction score
0

Homework Statement


I measured the weight(in Newtons), mass(in Kilograms), and volume(in cubic meters) of some objects. Then I tried to calculate the mass density and the weight density of the objects.


Homework Equations


Weight Density = weight/volume

Mass Density = mass/volume

ex. weight density of object one ... 2.00 N / 2.55x10-5 m3 = 78431 ??
mass density of object one ... .204kg / 2.55x10-5 m3 = 8000 ??

The Attempt at a Solution



I have found my numeric answers but i do not know what units the weight density and mass density are measured in. Would the weight density be measured in Newtons/ cubic meters and the mass density in kg/ cubic meters?
 
Physics news on Phys.org
GreenEyedGal3 said:

Homework Statement


I measured the weight(in Newtons), mass(in Kilograms), and volume(in cubic meters) of some objects. Then I tried to calculate the mass density and the weight density of the objects.


Homework Equations


Weight Density = weight/volume

Mass Density = mass/volume

ex. weight density of object one ... 2.00 N / 2.55x10-5 m3 = 78431 ??
mass density of object one ... .204kg / 2.55x10-5 m3 = 8000 ??

The Attempt at a Solution



I have found my numeric answers but i do not know what units the weight density and mass density are measured in. Would the weight density be measured in Newtons/ cubic meters and the mass density in kg/ cubic meters?
Yes, those would be the unit's to use. However, you may want to re-check your calculations.
 
I keep getting the same thing on my calculations. Should i round to the right number of significant digits or should i change my calculator from degrees to radians?
 
Hootenanny said:
However, you may want to re-check your calculations.
The calculations look fine. Are you hinting about the numbers? It looks to me like the OP was using stainless steel.

GreenEyedGal3 said:
should i change my calculator from degrees to radians?
What makes you think that this will make any difference?
 
D H said:
The calculations look fine. Are you hinting about the numbers? It looks to me like the OP was using stainless steel.
I was referring to the disparity between the weight of the object and the given mass multiplied by g:

(0.204*9.81)/(2.55*10-5) = 78480
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top