Weight of a Box between two fluids of different densities

AI Thread Summary
The discussion focuses on determining the mass of a box floating between two fluids with different densities, using variables such as height, cross-sectional area, and fluid densities. An initial equation derived from a free body diagram suggests a mass calculation, but there is confusion regarding the application of Archimedes' principle. The user realizes that the buoyant forces from both fluids must be considered, leading to a corrected understanding of the pressures acting on the box. The pressures at the top and bottom of the box are crucial for accurately calculating the forces involved. Ultimately, the user gains clarity on the relationship between buoyancy and fluid pressure in this scenario.
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Homework Statement


A box with a height L, and a cross sectional Area A is floating between two fluids of densities p1 and p2. Determine the mass of the box using ho, h1, h2, p1, p2, and A.


Homework Equations


F= pVg


The Attempt at a Solution



In the file attached I drew my free body diagram and the image of the box. Solving my FBD I get:

mg+p1(A)(ho)g=p2(A)(h2)g

Solving for m:

p2(A)(h2)-p1(A)(ho)

but with Archimedes principal the answer should be p2(A)(h2)+p1(A)(h1), so what did I do wrong/forget?

Thanks
 

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  • Drawing_FBD.jpg
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The bottom liquid is under the top liquid (obviously), but this has consequences for the pressures that are felt by the box in the bottom liquid.
 
So the only thing I can think of is the pressure of the top liquid acting on the bottom liquid, as well as the buoyancy of the bottom liquid with respect to the top liquid.

Im assuming these two forces are equal to each other Fb= (h1+h0)A*p1. If I include the buoyancy of liquid 2 on liquid 1 on the box diagram it does give me the answer I want, but I don't conceptually understand why.
 
Write the expressions for the pressures at the bottom of the box and the top of the box (at depths h0 and h0+h1+h2).
 
Ahh, I see thanks now it makes sense.
 
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