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Weight on a vertical curve

  1. Oct 27, 2009 #1
    1. The problem statement, all variables and given/known data
    A 50.0kg stunt pilot who has been diving her airplane vertically pulls out of the dive by changing her course to a circle in a vertical plane.

    If the plane's speed at the lowest point of the circle is 95.0m/s, what should the minimum radius of the circle be in order for the acceleration at this point not to exceed 3.00 g?
    Correct Answer for that was 307m

    Question i need help on is:
    What is the apparent weight(in Newtons) of the pilot at the lowest point of the pullout?


    2. Relevant equations

    W = mg
    g=v^2/r
    1g = 9.81

    3. The attempt at a solution

    I assumed that the easy solution would be to find the weight at 3g's so:
    50*3*9.81 = 1471.5

    Wasn't accepted as correct answer so i decided to solve it like:
    F = ma = m(v^2)/r
    50*(95^2)/307 = 1469.9

    Also, not taken as the correct answer.


    Please let me know what I am missing here
    Thanks,
    ~John
     
  2. jcsd
  3. Oct 27, 2009 #2
    the acceleration of the plane is 3g, but did earth's gravity turn off?
     
  4. Oct 27, 2009 #3
    Ok ok! Its ok everyone! I turned the gravity back on! ^_^

    Thank you for the help. I didnt think to add that in there and it worked beautifully
    ~John
     
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