- #1
raiderIV
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Homework Statement
A 50.0kg stunt pilot who has been diving her airplane vertically pulls out of the dive by changing her course to a circle in a vertical plane.
If the plane's speed at the lowest point of the circle is 95.0m/s, what should the minimum radius of the circle be in order for the acceleration at this point not to exceed 3.00 g?
Correct Answer for that was 307m
Question i need help on is:
What is the apparent weight(in Newtons) of the pilot at the lowest point of the pullout?
Homework Equations
W = mg
g=v^2/r
1g = 9.81
The Attempt at a Solution
I assumed that the easy solution would be to find the weight at 3g's so:
50*3*9.81 = 1471.5
Wasn't accepted as correct answer so i decided to solve it like:
F = ma = m(v^2)/r
50*(95^2)/307 = 1469.9
Also, not taken as the correct answer.
Please let me know what I am missing here
Thanks,
~John