- #1

- 31

- 0

**Neptune has a masss 17.2 times larger than that of Earth and a radius 3.88 times larger. A person weighing 176 lb on the Earth would weigh how much on Neptune?**

Earth's mass is 6x10^24; Earth's radius is 6.4x10^6. Neptune's mass is 1.032x10^26; Neptune's radius is 24832000. 176 lbs is 80 kgs.

Earth's mass is 6x10^24; Earth's radius is 6.4x10^6. Neptune's mass is 1.032x10^26; Neptune's radius is 24832000. 176 lbs is 80 kgs.

**Weight (or Force) = G[itex]\frac{Mplanet\bullet Mperson}{r2}[/itex]**

G (universal) = 6.7x10^-11

Mperson for Earth = 80 kgs

Mplanet for Earth = 6x10^24 kgs

r for Earth = 6.4x10^6

Mperson for Neptune = ?

Mplanet for Neptune = 1.032x10^26

r for Neptune = 24832000

**Every time I try to solve for the mass of the person on Neptune, I keep getting around 70 kgs, which is 154 lbs. The correct answer according to my online homework system is 201.084048 lbs.**

First, I solve for Force on Earth. I plug all four values into the equation to get 785.15625 Newtons.

Second, I then plug the answer above into the Force value to solve for Mperson on Neptune. To isolate Mperson I multiply both sides of the equation by r^2, divide both sides of the equation by G, and divide both sides of the equation by Mplanet. The answer I get is 70.02 kgs, which is 154.05 lbs. That is not the correct answer.

First, I solve for Force on Earth. I plug all four values into the equation to get 785.15625 Newtons.

Second, I then plug the answer above into the Force value to solve for Mperson on Neptune. To isolate Mperson I multiply both sides of the equation by r^2, divide both sides of the equation by G, and divide both sides of the equation by Mplanet. The answer I get is 70.02 kgs, which is 154.05 lbs. That is not the correct answer.

I know that all I really need to do is divide 3.88^2 by 17.2, then multiply that value by 176, but I want to find out what I'm doing wrong. I don't want to use any shortcuts until I actually understand the long process.

Thanks!