What Angles Affect the Vector Components of a Weight on an Inclined Plane?

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Homework Help Overview

The discussion revolves around the vector components of weight acting on a book sliding down a frictionless inclined plane. The original poster poses questions regarding specific angles at which the components of weight are equal or zero.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster expresses uncertainty about how to approach the problem and suggests that the components might be equal at 45 degrees. Other participants prompt the poster to visualize the problem by considering the components of weight acting parallel and perpendicular to the incline.

Discussion Status

Some participants have provided guidance by suggesting visualization techniques, while the original poster has indicated some progress in understanding the relationships between the angles and the vector components. However, there is no explicit consensus on the interpretations of the angles or the reasoning behind them.

Contextual Notes

The original poster's questions imply a need for clarification on the definitions and relationships of vector components in the context of inclined planes, but specific assumptions or constraints have not been detailed.

dandy9
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Homework Statement


The weight of a book sliding down a frictionless inclined plane can be broken into two vector components: one acting parallel to the plane, and the other acting perpendicular to the plane.
(a) At what angle is the components equal?
(b) At what angle is the component parallel to the plane equal to zero?
(c) At what angle is the component parallel to the plane equal to the weight?

Homework Equations


Fnet = ma

The Attempt at a Solution


I'm not really sure how to approach this.
My guess for (a) is 45 just because it sounds reasonable that the components would be equal at the middle of 0 to 90 degrees.
 
Physics news on Phys.org
try to imagine a book on a inclined plane inclined at say angle a...
If weight is mg, component of weight perpendicular to incline is ..?
what is the component of weight parallal to incline?

draw figure and then you'll easily solve it
 
Thank you!

I got them all - thanks for getting me started! This is how I did it:
(a) cos and sin are equal at 45degrees
(b) the sin of 0 gives a component of 0.
(c) if the component and weight are equal then you take the inverse sin of 1 and get 90.
 
Very good.
 

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