What are axial and peripheral ligands in coordination chemistry?

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    Axial Ligands
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The discussion centers on the definitions and roles of "axial ligands" and "peripheral ligands" in coordination chemistry, particularly in the context of a specific molecular structure involving porphyrin rings and metal ligands. Axial ligands are positioned along the axis of a coordination complex, while peripheral ligands are located in the equatorial plane. The example provided illustrates that the bridging oxygen atom between two metal ligands can indeed be classified as an axial ligand, despite the common perception of oxygen as an electron donor. The conversation clarifies that in geometries such as trigonal bipyramidal or octahedral, the distinction between axial and peripheral ligands is based on their spatial arrangement relative to the central metal atoms. This understanding is essential for interpreting the structural and electronic properties of coordination complexes.
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In this article:
http://jredman.kombyonyx.com/thesis/Ch16.htm
they mention "axial ligands" and "peripheral ligands". What exactly does that mean? Heres the molecule they use as an example:
http://jredman.kombyonyx.com/thesis/Ch16_files/image002.gif
I can see that the porphyrin rings both have a metal ligand M binded to them. That oxygen atom which bridges the two M ligands, is that an "axial ligand"? Is it even a ligand at all, I thought a ligand meant an electrophilic species which accepts electrons from an electron doner and forms a dative bond. I'm used to oxygen atoms being an electron doner.
 
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Axial and peripheral refer to the positions in complexes displaying geometries like that of trigonal bipyramidal or octahedral. In the former case you can think of three ligands which make up the "base" of each pyramid as equatorial/peripheral and the two other ligands as the axial. The same idea is applied to octahedral complexes, notice the pyrrole nitrogen a are equatorial and with the bridging O being axial in both metals (so is the thing at the very top but my phone won't show me the full size picture).
 
That explains it, thanks a lot.
 
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