What are common issues when using 2N2222 in a BJT NPN amplifier?

  • Thread starter Thread starter Ivan Antunovic
  • Start date Start date
  • Tags Tags
    Bjt Npn Transistor
Click For Summary

Discussion Overview

The discussion revolves around common issues encountered when using the 2N2222 transistor in a BJT NPN amplifier configuration. Participants explore problems related to output voltage, determining hybrid output resistance, and small signal analysis. The conversation includes technical details, design considerations, and troubleshooting steps.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant reports no AC voltage at the output and suspects an incorrect operating point.
  • Another participant questions the frequency and amplitude of the input signal, suggesting that low resistor values may be affecting performance.
  • Concerns are raised about the negligible hybrid output resistance (hoe) and its relevance to the design.
  • Participants discuss the impact of coupling capacitor sizes on signal attenuation, particularly at a frequency of 50Hz.
  • One participant mentions a new task assigned by a professor to design a common emitter amplifier with specific parameters, including power dissipation and output voltage requirements.
  • There is confusion regarding the voltage supply used in calculations, with one participant acknowledging a mistake in referencing 15V instead of the specified 12V.
  • Discussion includes the need to calculate resistances for biasing and the implications of power dissipation in the circuit.
  • Participants express uncertainty about the values of resistances needed for proper biasing and the overall design of the circuit.

Areas of Agreement / Disagreement

Participants express multiple competing views regarding the design and troubleshooting of the amplifier. There is no consensus on the best approach to resolve the issues presented, and various suggestions are made without agreement on a single solution.

Contextual Notes

Participants mention limitations related to the design, such as the choice of coupling capacitors and the operating point settings. There is also uncertainty regarding the calculations for resistances and power dissipation, which depend on various assumptions and parameters.

Who May Find This Useful

This discussion may be useful for electronics students, hobbyists working on amplifier designs, and individuals interested in troubleshooting BJT amplifier circuits.

Ivan Antunovic
Messages
109
Reaction score
4
Hello people,

I am working on a BJT NPN amplifier the model that I've choosen is 2N2222 : http://www.e-voron.dp.ua/files/pdf/tranzistor/2N2222.pdf

I am having 3 problems here:

1) am not having any AC voltage at output Vce seems like I have set wrong operating point?

2) I am trying to figure out how to determine hoe resistance of this transistor from the graph hybrid output resistance hoe=dIc/dUce at operating point Q

3)Is my schematics for the small signal analysis wrong?

I hope pictures are not blur.
 

Attachments

  • BJT NPN Shema.jpg
    BJT NPN Shema.jpg
    79.9 KB · Views: 574
  • DSC_0789 (1).JPG
    DSC_0789 (1).JPG
    17.4 KB · Views: 492
  • DSC_0790 (1).JPG
    DSC_0790 (1).JPG
    25.6 KB · Views: 481
Physics news on Phys.org
Okay they are blur
BJT_NPN_Shema.jpg

DSC_0792.jpg

http://postimage.org/
 
Last edited by a moderator:
Ivan Antunovic said:
Okay they are blur
BJT_NPN_Shema.jpg
and Xce should be in parallel with Re my bad
DSC_0792.jpg

http://postimage.org/
 
Last edited by a moderator:
Ivan Antunovic said:
Hello people,

I am working on a BJT NPN amplifier the model that I've choosen is 2N2222 : http://www.e-voron.dp.ua/files/pdf/tranzistor/2N2222.pdf

I am having 3 problems here:

1) am not having any AC voltage at output Vce seems like I have set wrong operating point?

What's your frequency and amplitude? Your RC and RT are both very low.
2) I am trying to figure out how to determine hoe resistance of this transistor from the graph hybrid output resistance hoe=dIc/dUce at operating point Q
forget about hoe. It's negligible.
3)Is my schematics for the small signal analysis wrong?
No idea. Depends on your software. Your schematic in post 2 does not show a signal source ...
 
rude man said:
What's your frequency and amplitude? Your RC and RT are both very low. forget about hoe. It's negligible.
No idea. Depends on your software. Your schematic in post 2 does not show a signal source ...

Okay forgotten to say about voltage source it's sinus with amplitude 100 mV and frequency 50Hz
 
Ivan Antunovic said:
Okay forgotten to say about voltage source it's sinus with amplitude 100 mV and frequency 50Hz

I know that hoe is so small but I am trying to do things atleast as correct as I can I do this for my soul.There is Ic-Uce curve in the link that I've given but it's in logaritmic paper how to I convert it from dB to Ampers and Volts?
 
Due to C1 being so large you should be seeing a horribly distorted sine wave at the collector of about 200 mV.
At the output there is very little ac since the time constant formed by RC, RT and CV2 is very low (cutoff freq. about 2 KHz).

This is a really bad design so worrying about hoe is a total waste of time.
What does your simulator say?

.
 
rude man said:
Due to C1 being so large you should be seeing a horribly distorted sine wave at the collector of about 200 mV.
At the output there is very little ac since the time constant formed by RC, RT and CV2 is very low (cutoff freq. about 2 KHz).

This is a really bad design so worrying about hoe is a total waste of time.
What does your simulator say?

.
I have taken schematics from the internet,voltmeter shows no voltage at output and oscilloscope shows no signal at output
 
Ivan Antunovic said:
Okay forgotten to say about voltage source it's sinus with amplitude 100 mV and frequency 50Hz

For a signal frequency of 50Hz your coupling capacitors are way too small; they are attenuating the signal more than the 2222 is amplifying it. What is the reactance of a 1uF capacitor at 50Hz?
 
  • #10
NascentOxygen said:
For a signal frequency of 50Hz your coupling capacitors are way too small; they are attenuating the signal more than the 2222 is amplifying it. What is the reactance of a 1uF capacitor at 50Hz?
it's 3813 ohms.Okay then make it 10kHz so the reactance goes down by 200
 
  • #11
Forget about this task it has very bad resistances.

I got a new task from my professor:

Compile common emmiter amplifier(NPN) with the following default parameters:

VCC = 12V, power transistor 50 mW max. output signal between 3-5V, VRE = 1V.

Determine Computing and measuring AV, AI, Rin, Rout, the upper and lower limit frequency, THD.

Then, instead of RL connect the speaker and try something heard on the speaker.

I have choosen transistor BC547.

I assumed that the voltage at RL is 5V and from PRL=VRL^2 / RT I get that RL=250 ohms.I measured that Vbe=0.68V.

I am trying to figure out what should be resitances R1 and R2
transistor.jpg
image upload no limit
 
  • #12
Ivan Antunovic said:
Forget about this task it has very bad resistances.

I got a new task from my professor:
Compile common emitter amplifier(NPN) with the following default parameters:
VCC = 12V, power transistor 50 mW max. output signal between 3-5V, VRE = 1V.
Determine Computing and measuring AV, AI, Rin, Rout, the upper and lower limit frequency, THD.
Then, instead of RL connect the speaker and try something heard on the speaker.
I have choosen transistor BC547.
I assumed that the voltage at RL is 5V and from PRL=VRL^2 / RT I get that RL=250 ohms.I measured that Vbe=0.68V.
I am trying to figure out what should be resitances R1 and R2
R1 and R2 are chosen to give you the required 1V at the emitter. Consider the base dc current also.
The professor meant to limit your dissipation to 50 mW, not that the transistor cannot sustain more than 50 mW, probably.
EDIT:
I didn't see the 1V VRE requirement. So this will not be a real common-emitter circuit.
What are your upper and lower frequencis?
You can probably connect the speaker in series with the collector resistor.
 
Last edited:
  • Like
Likes   Reactions: Ivan Antunovic
  • #13
Ivan Antunovic said:

I got a new task from my professor:

Compile common emmiter amplifier(NPN) with the following default parameters:

VCC = 12V, power transistor 50 mW max. output signal between 3-5V, VRE = 1V.
The specs say Vcc = 12V, yet your calculations use Vcc of 15V. Why? :oldconfused:
 
  • #14
NascentOxygen said:
The specs say Vcc = 12V, yet your calculations use Vcc of 15V. Why? :oldconfused:
My bad I was really tired at evening when doing this that I didn't even notice it was 15 V.
 
  • #15
How do you mean it won't be real common emitter circuit when it has a resistor RC connected directly to the collector electrode?R1 and R2 are voltage dividers I know that they are used to set Quiescent Point.If R1 and R2 are voltage dividers of Vcc and if I want 13.35 V at R1 and 1.65 V at R2,R1 should be 8.09 times larger than R2.

Edit(after drinking a coffee :D):
Btw I am using BC547 for this circuit https://www.fairchildsemi.com/datasheets/BC/BC547.pdf maybe I should take some data from the datasheet and try calculating resistances.For example there is a Ic-Vce curve and I tried to make load line and then it's a piece of cake for finding the resistances.

Load line equation is:
Ic=-Uce/Rc+Re + Ucc/Rc+Re (Asumming that Ic=Ie)the maximum Vce voltage is Vcc which is 12 volts ,maximum current Ic will flow when Ucc/Rc+Re and therefore it's y-intercept of the curve.But still I don't know Rc and Re so therefore I can't find y-intercept...maybe I should consider a worst case scenario and take values for Vce ,Ic and Ib from the datasheet?
 
Last edited:
  • #16
If you're aiming for 50mW dissipation, and you bias for VCE of around 6-7V, then what will be the DC value of IC?
 
  • #17
NascentOxygen said:
If you're aiming for 50mW dissipation, and you bias for VCE of around 6-7V, then what will be the DC value of IC?

Well I don't know since I am trying to figure out how to find R1 and R2 since they determine the bias IB and then IC.If I assume that Vce is around 6 V then VRC=VCC-VCE-VRE=12-1-6= 5 V but still I don't know the value of the resistance RC?
 
  • #18
power dissipation = voltage x current

- which voltage?
- which current?

Remember that power into the base is a negligible fraction of total power, for these small signal amplifiers.
 
  • #19
NascentOxygen said:
power dissipation = voltage x current

- which voltage?
- which current?

Remember that power into the base is a negligible fraction of total power, for these small signal amplifiers.
I think he meant power dissipated at the output load resistance
 
  • #20
Yes power into the base is negligible but I didnt understand first part of your post?
 

Similar threads

  • · Replies 17 ·
Replies
17
Views
3K
Replies
4
Views
20K
Replies
16
Views
11K
Replies
11
Views
3K
  • · Replies 25 ·
Replies
25
Views
10K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 9 ·
Replies
9
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
9
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K