What Are the a and b Values in the Complex Form of i?

[algebra2]

Homework Statement

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how are the solutions of the fourth roots pi/2? how do you get pi/2, you know the thing after "cos" and "isin" ?

 

[sutupidmath]

First write it in polar form, or trigonometric form, however you call it, and after that use de moivre's formula to find its roots.

let z be a complex nr.

z=a+bi, writing it in polar forms : a=r cos(\theta),b=\ro sin\theta


So,

z=r (cos\theta+isin\theta)

now

z^{\frac{1}{n}}=r^{\frac{1}{n}}(cos\frac{\theta +2k\pi}{n}+isin{\frac{\theta+2k\pi}{n})

Now all you need to do is figure out what \theta is, and your fine.

Or if you want the exponential representation of a complex nr:

e^{ix}=cosx+isinx

e^{i\frac{\pi}{2}}=i so we get

i=cos\frac{\pi}{2}+isin\frac{\pi}{2}

 

[algebra2]

e^{i\frac{\pi}{2}}=i

how do you know that x = pi/2

 

[sutupidmath]

well z=i, is a complex nr right. Following my elaboration above we have a=0, b=1, right?

so \theta =\arctan\frac{1}{0}-->\frac{\pi}{2} loosly speaking.

so the exponential form of i is what i wrote i=e^{i\frac{\pi}{2}}

SO to find the four roots of i just follow de moivres formula that i wrote above, letting k=0,1,2,3.

 

[algebra2]

how do you know a=0 and b=1? isn't it a=1 and b=-1 or did i do something wrong

 

[HallsofIvy]

Your number is i. If you write that in the form a+ bi, what are a and b?