What Are the Characteristics of Oscillations for a Box on a Spring?

  • Thread starter Thread starter mattmannmf
  • Start date Start date
  • Tags Tags
    Oscillations
AI Thread Summary
The discussion focuses on the characteristics of oscillations for a box on a spring, with the position described by the equation x = 5.3 m * cos(20/sec * t). The amplitude of the oscillations is identified as 5.3 m, while the angular frequency (ω) is noted as 20 s^-1. The participants are calculating the position of the box at 2 seconds, with initial attempts yielding incorrect results. The calculations involve substituting values into the cosine function, indicating a need for clarification on the correct approach. The conversation emphasizes understanding the relationship between amplitude, angular frequency, and the resulting motion of the box.
mattmannmf
Messages
170
Reaction score
0
the position of the center of the box shown is given by the equation

x = 5.3 m * cos(20/sec * t)
(a) What is the position of the box 2 seconds after the oscillations have started?

(b) What is the amplitude of the box's oscillations?

(c) What is the period of the box's oscillations?

(d) What is the box's maximum velocity?

(e) What is the box's maximum acceleration?

(f) How long does it take the box to move from -2.65 m to +2.65 m?

for a, i just plugged in 2 for t and got 4.98...but that's wrong not sure where to go from there
Calc:
5.3*cos(20/(1/cos(2)))...sec= 1/cos
 
Physics news on Phys.org


Start with x = A cos (ωt). What is A? What is ω?

A = 5.3 m, and ω = 20 s-1
 


so x=5.3*cos(20E-1*2)...5.28?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top