What are the Cross Products of Vectors AB and AD in Calculus 3?

GreenPrint
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Homework Statement



see attachment

Homework Equations





The Attempt at a Solution



i found AB got <4,2,3>
i found AD got <1,-1,1>
i found |ABxAD| got square root of 62

not exactly sure what i am doing wrong thanks for any help
 

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GreenPrint said:

Homework Statement



see attachment

Homework Equations





The Attempt at a Solution



i found AB got <4,2,3>
i found AD got <1,-1,1>
i found |ABxAD| got square root of 62

not exactly sure what i am doing wrong thanks for any help

I'd like to know how you got <1,-1,1> for AD.
 
oh dang thanks man
 

Thread 'Finding the nth roots of a complex number'

There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
View full post »

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