What Are the Permissible (L,S) Pairs for J=1 in a System of Two Spin-1 Bosons?

c299792458
Messages
67
Reaction score
0

Homework Statement



We have a system of 2 indistinguishable spin-1 bosons. We shall adopt the center of mass frame.

Let
S = total spin
L = relative orbital angular momentum
J = L+S = total angular momentum

Prove that J = 2m where m is an integer.
If given that J=1, what are the permissible (L,S) pairs?

Homework Equations


Bose-Einstein Stats?

The Attempt at a Solution


I am lost with this. I have managed to show that for the states S=0, S=2 interchanging particles 1,2 is symmetric, whereas it is antisymmetric for S=1. However, I don't know how to use this here.
What is the significance of the CoM frame choice?
Also, due to Bose-Einstein stats, the overall wavefunction should be symmetric under the interchange of the 2 bosons. However, I don't know how even and odd wavefunctions for orbital angular momentum behave. Anyone please?
 
Last edited:
Physics news on Phys.org
No worries. Problem resolved. Thanks for reading anyways.
 
##|\Psi|^2=\frac{1}{\sqrt{\pi b^2}}\exp(\frac{-(x-x_0)^2}{b^2}).## ##\braket{x}=\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dx\,x\exp(-\frac{(x-x_0)^2}{b^2}).## ##y=x-x_0 \quad x=y+x_0 \quad dy=dx.## The boundaries remain infinite, I believe. ##\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dy(y+x_0)\exp(\frac{-y^2}{b^2}).## ##\frac{2}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,y\exp(\frac{-y^2}{b^2})+\frac{2x_0}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,\exp(-\frac{y^2}{b^2}).## I then resolved the two...
Hello everyone, I’m considering a point charge q that oscillates harmonically about the origin along the z-axis, e.g. $$z_{q}(t)= A\sin(wt)$$ In a strongly simplified / quasi-instantaneous approximation I ignore retardation and take the electric field at the position ##r=(x,y,z)## simply to be the “Coulomb field at the charge’s instantaneous position”: $$E(r,t)=\frac{q}{4\pi\varepsilon_{0}}\frac{r-r_{q}(t)}{||r-r_{q}(t)||^{3}}$$ with $$r_{q}(t)=(0,0,z_{q}(t))$$ (I’m aware this isn’t...
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
Back
Top