What are the phase factors for the atoms in this quantum state?

AI Thread Summary
The discussion revolves around determining the quantum state of pre-selected atoms based on their spin measurement probabilities in different directions. The measured probabilities indicate a spin-up result of 5/6 in both the x and y directions, and 1/3 in the z direction. The user initially calculates the probability amplitudes for the z-basis but is confused about the need for measurements in all three directions to fully characterize the state. It is clarified that while the user has found the magnitudes of the amplitudes, the complex phase factors must also be considered for a complete description of the quantum state. The conversation emphasizes the importance of understanding both the magnitudes and phases in quantum mechanics.
phil ess
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Homework Statement



Assume there is a source of some pre-selected atoms. When measuring atoms of that source in a Stern-Gerlach, you find the following probabilities for a spin-up result:

x-direction 5/6
y-direction 5/6
z-direction 1/3

Which state would you ascribe to the source?

Homework Equations



?

The Attempt at a Solution



Let the atoms be:

\[ \left( \begin{array}{ccc}<br /> \alpha \\<br /> \beta \end{array} \right)\]

Decomposing in the z-basis we get that the probability amplitudes for up and down are |\alpha|^2 and |\beta|^2, respectively.

From this we find that \alpha = 1/\sqrt{3} and \beta = \sqrt{2/3}

Ok this is where I am confused, my textbook says we need to do a measurement in all 3 directions, but I got these values with just the z result?

If someone could explain this to me itd be a big help, I am stuck :(
 
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phil ess said:

Homework Statement



Assume there is a source of some pre-selected atoms. When measuring atoms of that source in a Stern-Gerlach, you find the following probabilities for a spin-up result:

x-direction 5/6
y-direction 5/6
z-direction 1/3

Which state would you ascribe to the source?

Homework Equations



?

The Attempt at a Solution



Let the atoms be:

\[ \left( \begin{array}{ccc}<br /> \alpha \\<br /> \beta \end{array} \right)\]

Decomposing in the z-basis we get that the probability amplitudes for up and down are |\alpha|^2 and |\beta|^2, respectively.

From this we find that \alpha = 1/\sqrt{3} and \beta = \sqrt{2/3}

Ok this is where I am confused, my textbook says we need to do a measurement in all 3 directions, but I got these values with just the z result?

If someone could explain this to me itd be a big help, I am stuck :(
Be careful, you have not actually found α and β. You have found |α| and |β|. There is a complex phase factor still to be accounted for.
 
Hmmm, ok well what I have here is, if |a|2 + |b|2 = 1, then |a|2 - |b|2 is a number between 1 and -1, so we write:

|a|2 - |b|2 = cos 2x, where x is between 0 and pi/2

then

|a|2 = 1/2 (|a|2 + |b|2) + 1/2 (|a|2 - |b|2)
|a|2 = 1/2 + 1/2 (cos 2x) = cos2x

and similarly

|b|2 = sin2x

so then

\alpha = e^i^\varphi cos x
\beta = e^i^\phi sinx

and then these are the phase factors you are talking about? I know they have magnitude 1, but I am not sure I know how to proceed from here :S
 
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