What are the tensions in the two ropes holding up a ball?

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To determine the tensions in the two ropes holding up a ball weighing 8.0N, start by drawing a free body diagram to visualize the forces acting on the ball. Identify the forces, including the weight of the ball and the tensions in the ropes, T1 and T2. Sum the forces in the x (horizontal) and y (vertical) directions, noting that the net force must equal zero for the ball to remain at rest. Tension in the ropes can be calculated using trigonometric relationships based on the angles and the weight of the ball. This systematic approach will lead to the solution for the tensions T1 and T2.
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A ball is hanging from two ropes conjoining into one.One leads horizontally to the left and the other up at a 30 degree angle from the ceiling.



The ball weighs 8.0N
what are the tensions on T1 and T2?

How can i start on this?
 
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Start of with a free body diagram. Always draw a free body diagram with these types of problems. Then identify all the forcecs. Then sum up the forces in the x and y directions.
 
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Well, tension is equal to the force that is applied. So if the object stands in a position of rest you know the sum of some component is zero. Ask yourself the question; in what direction those components act and how can you calculate them.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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