What Are the Two Angles for a Fire Hose to Reach 2.0 Meters?

AI Thread Summary
To determine the angles for a fire hose to reach 2.0 meters with a water speed of 6.8 m/s, the projectile motion equations must be applied. The time of flight is calculated using the vertical motion formula, leading to t = 2 * 6.8 * sin(angle) / 9.81. The horizontal distance equation, dx = vix * t, is then used to relate the horizontal distance to the angle. There are two angles because of the nature of projectile motion, where both a steep and a shallow angle can achieve the same horizontal range. Understanding these calculations is essential for solving the problem effectively.
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Homework Statement


A fire hose held near the ground shoots water at a speed of 6.8 m/s. At what angle(s) should the nozzle point in order that the water land 2.0 m away? Why are there two different angles?

The Attempt at a Solution


First, I don't know why there would be two angles. I only found the formula, but I don't know how to solve the angle out. I found t=2* 6.8sinangle/9.81(I don't know how to use the angle symbol) dx=vix*t, 2=6.8cosangle*2*6.8sinangle/9.81. How to find the angle?

Thank you.
 
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I found t=2* 6.8sin(angle)/ 9.81. dx=vix*t, 2=6.8cos(angle)*2*6.8sin(angle)/9.81. How to find the angle? I rewrite it because I just want to make sure you understand what I am talking about. Really hope someone can help me! thanks.
 

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