What Causes the Net Torque on a Uniform Disk?

AI Thread Summary
The net torque on a uniform disk with a mass of 34.8 kg and a radius of 0.32 m, subjected to forces of 90.0 N and 125 N, is calculated using the formula Torque = rFsin(theta). The resulting torque is -11.2 N*m, indicating a clockwise direction based on the convention that counterclockwise is positive. The discussion confirms that the provided information is accurate, and the negative sign reflects the direction of the torque. The next inquiry involves determining the magnitude of the disk's angular acceleration.
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[SOLVED] Net torque of uniform disk

Homework Statement


A uniform disk with a mass of 34.8 kg and a radius of 0.32 m is free to rotate about a frictionless axle. Forces of 90.0 N and 125 N are applied to the disk, as the drawing indicates.

What is the net torque produced by the two forces?

Homework Equations


Torque = rFsin(theta)

The Attempt at a Solution


I've tried using the equation above...125(0.32)sin90 - 90(0.32)sin90 = 11.2 N*m which is wrong. I know this question is trivial, but I'm pretty frustrated at this point...any help would be great.
 
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Assuming the information given is correct, I agree with you that the magnitude of the torque is 11.2 Nm. My physics text usually considered counterclockwise as positive, with clockwise as the negative direction, so I actually got -11.2Nm. This isn't the problem right? If not I would check that you have the correct information.
 
G01 said:
Assuming the information given is correct, I agree with you that the magnitude of the torque is 11.2 Nm. My physics text usually considered counterclockwise as positive, with clockwise as the negative direction, so I actually got -11.2Nm. This isn't the problem right? If not I would check that you have the correct information.

It's the correct information, and the answer is -11.2. Thanks.
 
Anytime!
 


What is the magnitude of the angular acceleration of the disk?
 
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