What Conditions Determine the Existence of These Mathematical Limits?

pawlo392
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Hello . I have problems with two exercises .
1.\lim_{t \to 0 } \frac{2v_1-t^2v_2^2}{|t| \sqrt{v_1^2+v_2^2} }
Here, I have to write when this limit will be exist.
2.\lim_{(h,k) \to (0,0) } \frac{2hk}{(|h|^a+|k|^a) \cdot \sqrt{h^2+k^2} }
Here, I have to write for which a \in \mathbb{R}_+ this limit will equal to zero.
I don't have ideas how to do it.
 
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pawlo392 said:
Hello . I have problems with two exercises .
1.\lim_{t \to 0 } \frac{2v_1-t^2v_2^2}{|t| \sqrt{v_1^2+v_2^2} }
Here, I have to write when this limit will be exist.

Well, in a fraction, as the denominator approaches zero, then the fraction becomes undefined, unless the numerator also approaches zero. So under what circumstances does the numerator go to zero as t \rightarrow 0?
 
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Yes. Now I know. When v_1=0 this limit will equal to zero.
 
pawlo392 said:
Yes. Now I know. When v_1=0 this limit will equal to zero.
But the limit is as t approaches 0. As far as the limit process is concerned, ##v_1## is just some constant. You can't arbitrarily say it's zero.
 
Mark44 said:
But the limit is as t approaches 0. As far as the limit process is concerned, ##v_1## is just some constant. You can't arbitrarily say it's zero.

The question was when (in what circumstances) the limit exists. When v_1 = 0 is a possible circumstance.
 
pawlo392 said:
Hello . I have problems with two exercises .
1.\lim_{t \to 0 } \frac{2v_1-t^2v_2^2}{|t| \sqrt{v_1^2+v_2^2} }
Here, I have to write when this limit will be exist.
2.\lim_{(h,k) \to (0,0) } \frac{2hk}{(|h|^a+|k|^a) \cdot \sqrt{h^2+k^2} }
Here, I have to write for which a \in \mathbb{R}_+ this limit will equal to zero.
I don't have ideas how to do it.

For the second one, I would use polar coordinates ##h = r \cos \theta, k = r \sin \theta##, so that we are taking the limit as ##r \to 0##.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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