What Constant Makes a Function Holomorphic?

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Homework Statement



Find a constant k such that the function v(x,y) = y^3-4xy +kx^2y can be the imaginary part of a holomorphic function f on C

Homework Equations



The Cauchy-Riemann equations: u_x=v_y and u_y=-v_x

The Attempt at a Solution



So far I have taken the partial derivatives of v w.r.t y and equated it to u_x and then integrated w.r.t x giving:
u=3xy^2-2x^2y+(k/3)x^3+f(y)

Then differentiating w.r.t y to give:
u_y=6xy-2x^2y+(k/3)x^3y+f'(y)

Next I equate this to -v_x giving:
6xy-2x^2y+(k/3)x^3y+f'(y)=4y-2kxy

Now I am not sure which direction to head next or even if this is the correct approach to begin with. Help is greatly appreciated
 
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jimmycricket said:

Homework Statement



Find a constant k such that the function v(x,y) = y^3-4xy +kx^2y can be the imaginary part of a holomorphic function f on C

Homework Equations



The Cauchy-Riemann equations: u_x=v_y and u_y=-v_x

The Attempt at a Solution



So far I have taken the partial derivatives of v w.r.t y and equated it to u_x and then integrated w.r.t x giving:
u=3xy^2-2x^2y+(k/3)x^3+f(y)

Then differentiating w.r.t y to give:
u_y=6xy-2x^2y+(k/3)x^3y+f'(y)

Next I equate this to -v_x giving:
6xy-2x^2y+(k/3)x^3y+f'(y)=4y-2kxy

Now I am not sure which direction to head next or even if this is the correct approach to begin with. Help is greatly appreciated

You are working too hard. Can you show that Cauchy-Riemann implies ##v_{xx}+v_{yy}=0##? You don't really need to find u.
 
Last edited:
jimmycricket said:

Homework Statement



Find a constant k such that the function v(x,y) = y^3-4xy +kx^2y can be the imaginary part of a holomorphic function f on C

Homework Equations



The Cauchy-Riemann equations: u_x=v_y and u_y=-v_x

The Attempt at a Solution



So far I have taken the partial derivatives of v w.r.t y and equated it to u_x and then integrated w.r.t x giving:
u=3xy^2-\color{red}{2x^2y}+(k/3)x^3+f(y)

Then differentiating w.r.t y to give:
u_y=6xy-2x^2y+(k/3)x^3y+f'(y)

Next I equate this to -v_x giving:
6xy-2x^2y+(k/3)x^3y+f'(y)=4y-2kxy

Now I am not sure which direction to head next or even if this is the correct approach to begin with. Help is greatly appreciated

Your method is OK and will solve the problem. But you have mistakes in your work. Hard to point out your errors since you omitted some steps. In particular, the term in red is incorrect.
 
Dick and LCKurtz thanks both for replying. Dick: following your method I get v_{xx}+v_{yy}=2ky+6y=0 \rightarrow k=-3
This method is showing that the function is harmonic for k=-3. Is this sufficient for answering the question of which k makes the function holomorphic?
 
jimmycricket said:
Dick and LCKurtz thanks both for replying. Dick: following your method I get v_{xx}+v_{yy}=2ky+6y=0 \rightarrow k=-3
This method is showing that the function is harmonic for k=-3. Is this sufficient for answering the question of which k makes the function holomorphic?

Yes, if the function is holomorphic then v needs to be harmonic. So the only possible value is k=(-3).
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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