# What dictates electron spin?

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1. Jun 13, 2015

### Ryan Reed

Spin is an intrinsic property of particles meaning that they have it naturally. Electrons can have either +1/2 spin or -1/2, what dictates that it is one instead of the other?

2. Jun 13, 2015

### fzero

We do when we choose the convention for + vs -. Nature doesn't care which is which, it only knows that they are different.

3. Jun 13, 2015

### Ryan Reed

Then what is the difference? How could one tell that the electron has a +1/2 or a -1/2?

4. Jun 13, 2015

### fzero

Google for Stern-Gerlach experiment. Briefly, in an external magnetic field a magnetic dipole has an interaction energy $H_d = - \vec{\mu}\cdot \vec{B}$. Spin up and down have opposite signs in this formula (if all else is equal), so you could conspire to make a measurement that would distinguish them.

5. Jun 13, 2015

### Ryan Reed

And is the spin of the particle static, as in it doesn't change? Or can particle spin be flipped and changed?

6. Jun 13, 2015

### fzero

If we have a particle that we know to be in a definite spin state, then the spin can be flipped if we interact with it. From the same interaction, we can imagine that we can apply a nonconstant field that will rotate the dipole. If the dipole has rotated enough to now have the negative projection onto what we have decided is the axis we are using to measure spin, then we would say that the spin has flipped. This is really a classical point of view though. In the quantum picture, we are adding a small bit of the spin down state to the quantum state when we turn on the field. So there is always a nonzero probability to find that the spin has flipped due to the applied field. Tuning the field can have the effect of increasing the probability that the spin flips.

7. Jun 13, 2015

### Ryan Reed

How would you find these dipoles? I'm guessing that there is some way to tell since the magnetic field isn't distributed in the same way on the equator as on the poles.

8. Jun 13, 2015

### fzero

A particle with intrinsic spin is already a magnetic dipole, with dipole moment proportional to the spin vector. One learns this from the Stern-Gerlach type experiments that I've already mentioned.

9. Jun 13, 2015

### Ryan Reed

Thanks! This is exactly the kind of answers I was searching for!

10. Jun 13, 2015