What Do the Derivatives and Graphs Reveal About y=(2x+1)/\sqrt{x^2+1}?

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Homework Statement



y=(2x+1)/\sqrt{x^2+1}

Find where are the asymptotes, where is it increasing increasing/decreasing, ect...

Homework Equations





The Attempt at a Solution


when I took the first derivative (im trying to find where it increases/decrease), I got
dy/dx = \frac{2x^2-x+2}{(x^2+1)\sqrt{x^2+1}}

but there isn't any roots for this function... so what does that mean?
 
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No vertical asymptotes as x^2+1 can never be 0.

No horizontal asy as (x^2)^1/2 is one, and 2x is one.

Slant asymptote is synthetic division (x^2+1)^(1/2) |2x+1

If there are no 0's then that means that the equation always increases or decreases.
 
Grammer police: Better would be "either always increases or always decreases".


Any graph that does not have a horizontal line segment "always increases or decreases"!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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