What Does Number of Diameters Mean in Pipe Flow Analysis?

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Homework Help Overview

The discussion revolves around the concept of "number of diameters" in the context of pipe flow analysis, specifically addressing the relationship between pipe length and diameter in friction factor calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the meaning of expressing pipe length in terms of diameters and question the rationale behind the equation L = ND. There are inquiries about the implications of using L/D in friction factor equations and the observed similarities in flow properties across different pipe dimensions.

Discussion Status

The discussion is active, with participants seeking clarification on the definitions and implications of the number of diameters. Some have provided insights into the relationship between L/D and pressure drop, while others express confusion about specific aspects of the equations and concepts involved.

Contextual Notes

Participants are navigating through various interpretations of the equations and their practical applications, indicating a need for clearer explanations and understanding of the underlying principles.

foo9008
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Homework Statement


what is the meaning of number of diameter N ? why the author make L = ND ? and then divide it by D ?

Homework Equations

The Attempt at a Solution

 

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This is a practical way to do it: you get an equivalent length for fittings, elbows etc. that you can add to the sum of lengths of straight sections and use in friction factor formulas (e.g. Darcy).

Head loss is a function of ##L\over D## .

Didactically the sheet you show is indeed rather ready for improvement. I find it confusing.
 
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BvU said:
This is a practical way to do it: you get an equivalent length for fittings, elbows etc. that you can add to the sum of lengths of straight sections and use in friction factor formulas (e.g. Darcy).

Head loss is a function of ##L\over D## .

Didactically the sheet you show is indeed rather ready for improvement. I find it confusing.
can you explain about what is ND / D ? i am confused
 
ND is L so ND / D is L/D. That is the factor that appears in the friction factor equations such as Darcy and Fanning (*). The approach exploits the observed similarity in flow properties between a flow in a pipe of 100 m and 1 m diameter and a flow in a pipe of 10 m with a diameter of 10 cm.

(*)
And I would almost wish one of the two never existed :smile:. Now you have to be really careful if you divide 16 or 64 by Re for laminar flow...
 
BvU said:
ND is L so ND / D is L/D. That is the factor that appears in the friction factor equations such as Darcy and Fanning (*). The approach exploits the observed similarity in flow properties between a flow in a pipe of 100 m and 1 m diameter and a flow in a pipe of 10 m with a diameter of 10 cm.

(*)
And I would almost wish one of the two never existed :smile:. Now you have to be really careful if you divide 16 or 64 by Re for laminar flow...
why L = ND ? i don't understand it
 
Length of the pipe expressed in number of diameters. Nicely dimensionless. What can I say ?
 
BvU said:
Length of the pipe expressed in number of diameters. Nicely dimensionless. What can I say ?
what does it mean by number of diameter ?
 
The two pipes in #4 have the same ##{L\over D} = 10## so they will show the same pressure drop for a given fluid with widely different volume flows (factor 100) but the same flow velocity.
 
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BvU said:
The two pipes in #4 have the same ##{L\over D} = 10## so they will show the same pressure drop for a given fluid with widely different volume flows (factor 100) but the same flow velocity.
ys , they have L/ D of factor 100 ,why they will have the same pressure drop ?
 
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Allright, L/D = 100 o:) .
foo9008 said:
why they will have the same pressure drop
That's what has been observed to be the case :smile: .
'Apparently' ##\Delta p## is a function of L/D, something that probably also comes out of similarity considerations.

Something with ##{\rm Re} = {\rho v D\over \mu}##
 
  • #11
BvU said:
Allright, L/D = 100 o:) .
That's what has been observed to be the case :smile: .
'Apparently' ##\Delta p## is a function of L/D, something that probably also comes out of similarity considerations.

Something with ##{\rm Re} = {\rho v D\over \mu}##
ok , how does the case that you mentioned relate yo number of diameter ?
 

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