What does the graph look like if a = 0?

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In the equation x = xo + vot + (1/2)at^2, the graph of x versus t is parabolic when acceleration (a) is present due to the t^2 term. If acceleration is zero (a = 0), the graph becomes linear, reflecting only the initial velocity (v0). This linear graph indicates a constant rate of change in position over time. If v0 is negative or zero, the slope will adjust accordingly. Thus, the absence of acceleration simplifies the graph to a straight line.
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For the equation x = xo + vot + (1/2)at^2, what does a graph of x versus t look like? What does the graph look like if a = 0?
 
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1. parabolic
2. linear
 
if a = 0 it would look like a linear graph as in / considering v0 doesn't equal zero or is negative
otherwise it would look like x^2 just that it's moved to the left:


a+bx+cx^2:
Code:
   |  ||
   |  ||
   \__|/
______|_
      |

x^2:
Code:
   | | |
   | | |
   \_|_/
_____|___
     |
 
When there is acceleration, the graph would be parabolic because of the t^2

when a=0, there is only velocity and so the graph would be only a linear slope
 
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