What Does the Rayleigh Criterion Reveal About Image Resolution?

  • Thread starter Thread starter lha08
  • Start date Start date
  • Tags Tags
    Rayleigh
AI Thread Summary
The Rayleigh Criterion is a fundamental principle in optics that determines the minimum distance between two point sources for them to be distinguishable as separate images. It highlights that diffraction limits image resolution, causing close objects to appear smeared together. If two images are too close, they cannot be resolved individually, appearing as one blurred image. Understanding this criterion is essential for evaluating the resolution capabilities of optical instruments. Ultimately, the Rayleigh Criterion sets a threshold for image clarity in various imaging systems.
lha08
Messages
158
Reaction score
0

Homework Statement


I'm not sure but what exactly does the Rayleigh Criterion mean? Also, what does it mean when they say the "resolution" of the image...?
Thanks.


Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
No matter how good your instrument is there will be diffraction. So your image will be smeared a bit. Well if you have two images fairly close to each other you won't be able to resolve both of them if they lie too close to each other, since they are smeared a bit they will look like one image. The Rayleigh criterion defines how close the images can be together that you can still distinguish between the both of them.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top