What does translational energy have to do with entropy change?

AI Thread Summary
Translational energy of gas is expressed as 3/2NkT, where N is the number of molecules, k is Boltzmann's constant, and T is temperature. In an isothermal process, the change in entropy is calculated using the formula (delta)S = (integral from 1 to 2) dU/T + (integral from 1 to 2) PdV/T, with the dU/T term canceling out since U = 0. The remaining term, PdV/T, can be simplified using the ideal gas law, PV = NRT, to derive the entropy change as NRln(v2/v1). Understanding how translational energy relates to these calculations requires recognizing the role of temperature and volume in the ideal gas behavior. This connection emphasizes the interplay between energy, entropy, and the state of the gas.
giggidygigg
Messages
7
Reaction score
0
I know that the translational energy of gas can be represented by
3/2NkT
where N = number of molecules, k = boltzmann's constant, T = temperature

my textbook says that the change in entropy is
(delta)S = (integral from 1 to 2) dS = (integral from 1 to 2) dU/T + (integral from 1 to 2) PdV/T = NRln(v2/v1)

i know that since U = 0 in an isothermal system, dU/T term gets canceled and the PdV/T term is left, but i don't understand how we get NRln(v2/v1) from it

i also don't know how translational energy comes into place.

much help needed!
 
Science news on Phys.org
Try using the ideal gas law PV = NRT to put the P/T in terms of V. Hope this helps.
 
Thread 'Thermo Hydrodynamic Effect'
Vídeo: The footage was filmed in real time. The rotor takes advantage of the thermal agitation of the water. The agitation is uniform, so the resultant is zero. When the aluminum cylinders containing frozen water are immersed in the water, about 30% of their surface is in contact with the water, and the rest is thermally insulated by styrofoam. This creates an imbalance in the agitation: the cold side of the water "shrinks," so that the hot side pushes the cylinders toward the cold...
Back
Top