What Energy Maximizes Neutron Trapping in a Finite Square Well?

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Free particle --> bound particle

Homework Statement



A free neutron meets a finite square well of depth V_{0}, and width 2a centered around origo.

However, the probability that the neutron emits a photon when it meets the potential well, and thus decreasing its energy is proportional to the integral \int^{t_{1}}_{t_{0}}\int^{a}_{-a} |\Psi(x,t)|^{2} dx dt. Where t_{1}-t_{0} is the time it takes the neutron to cross the well.

The question then is: "What energy is the most advantageous for the neutron to have, in order to be trapped by the potential well?"


The Attempt at a Solution


The initial energy is E_{0}, the energy of the photon is E_{p}

I'm guessing I have to find a value for E_{0}, so as to make the integral a large as possible.
 
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Is there some form of ψ here that you are neglecting to tell us (like it is the wavefunction of the neutron)? If ψ is independent of E (or E0), then I don't see how it would make a difference (unless it's as silly as to realize to treat the neutron classically, so that t1-t0 depends inversely on the square root of E, which it may be, since it talks about "the time it takes the neutron to cross the well").
 
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