What Factors Affect the Tension on Cord C Before a Mass Hits the Ground?

  • Thread starter Thread starter bhannubhakta
  • Start date Start date
  • Tags Tags
    Tension
AI Thread Summary
The discussion focuses on calculating the tension in cord C before a mass hits the ground. The user calculates acceleration using the formula involving the masses and gravitational force, arriving at a value of 4.6. There is a question about whether tension can be determined by multiplying the sum of the masses by this acceleration. Participants clarify that the tension relates to the difference in the weights of the masses used in the acceleration calculation. Understanding these relationships is crucial for accurately determining the tension in the cord.
bhannubhakta
Messages
2
Reaction score
0
this is the image
cord.jpg


how do i find tension on cord C before one mass hits the ground?

i got the acceleration =(3.2-1.2/3.2+1.2)9.8 = 4.6
now is the tension sum of their masses times acceleration?
 
Physics news on Phys.org


bhannubhakta said:
this is the image
cord.jpg


how do i find tension on cord C before one mass hits the ground?

i got the acceleration =(3.2-1.2/3.2+1.2)9.8 = 4.6
now is the tension sum of their masses times acceleration?

Yes, but what is that?

Isn't it the difference in their weight that you used to calculate the acceleration in the first place?
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

Similar threads

Back
Top