What Force Lifts a Bicycle Wheel Over a Step?

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The discussion focuses on calculating the horizontal force required to lift a bicycle wheel over a step. The wheel's weight is 29.0 N, and its radius is 0.350 m, with the step height at 0.110 m. The key to solving the problem involves analyzing the torque around the point where the wheel contacts the step. By determining how the step divides the wheel's mass and calculating the center of mass for each part, the necessary force can be found. Understanding the relationship between the applied force and the resulting torque is crucial for finding the force at which the wheel begins to rise.
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The figure shows a bicycle wheel resting against a small step whose height is h = 0.110 m. The weight and radius of the wheel are W = 29.0 N and r = 0.350 m. A horizontal force F is applied to the axle of the wheel. As the magnitude of F increases, there comes a time when the wheel just begins to rise up and loses contact with the ground. What is the magnitude of the force when this happens?

I drew a diagram, yet I'm not even sure how to start this problem... help please! thanks!
 
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leezak said:
The figure shows a bicycle wheel resting against a small step whose height is h = 0.110 m. The weight and radius of the wheel are W = 29.0 N and r = 0.350 m. A horizontal force F is applied to the axle of the wheel. As the magnitude of F increases, there comes a time when the wheel just begins to rise up and loses contact with the ground. What is the magnitude of the force when this happens?
I drew a diagram, yet I'm not even sure how to start this problem... help please! thanks!
The step provides an axis (a line about which the wheel rotates) which divides the wheel into two parts. You have to determine how that axis divides the mass of the wheel. Then is a matter of determining the centre of mass of each part of the wheel to find the torques.

AM
 

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