What Formulas Do I Need to Ace My Physics Test Tomorrow?

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To prepare for the physics test, key formulas for solving problems involving friction and circular motion are discussed. For the ice skater question, the coefficient of friction is confirmed to be approximately 0.077, though the formula may vary. The radius of the exit ramp for the car is correctly calculated using the formula R = V²/(μg), yielding a radius of about 62.018 meters. For the pail of water, the minimum speed at the top of the circle is derived from the formula V = √(Rg), with the correct answer being approximately 3.13 m/s. Understanding these formulas and calculations is essential for success on the test.
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I am looking over my study and have a few questions. How would I solve some of these questions?

1) An ice skater moving at 12m/s coasts to a halt in 95m on an ice surface. What is the coefficient of friction between the ice and skates? QUESTION: is the formula to use for this always going to be -mew with little k = a with little x divided by g? Will the answer be -.077?

2) A car exits from the expressway to a circular exit ramp that posts a maximum exit speed of 35mph (15.6 m/s). If the typical coefficient of static friction between tires and pavement is 0.4, what is the radius of the exit ramp? QUESTION: Is this the formula i need to use to solve this R=Vsquared/mew times g ? The answer I got is 62.018m. Am i doing this right?

3) A pail of water is rotated in a vertical circle of radius 1m. What is the minimum speed of the pail at the top of the circle if no water is to spill out?
QUESTION: Is this the right formula Vsquared=RG? The answer I got is 3.03 m/s(squared) Am I on the the right track with this one?

Please help me do good on my test tomorrow. Any and all help would be greatly appreciated :smile:
 
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Hard to tell if its right without seeing the work, but these don't take a lot of calculations, so...

1) An ice skater moving at 12m/s coasts to a halt in 95m on an ice surface. What is the coefficient of friction between the ice and skates? [/B] QUESTION: is the formula to use for this always going to be -mew with little k = a with little x divided by g? Will the answer be -.077?
The answer is right. Also I would't say the formula is always going to be that.


A car exits from the expressway to a circular exit ramp that posts a maximum exit speed of 35mph (15.6 m/s). If the typical coefficient of static friction between tires and pavement is 0.4, what is the radius of the exit ramp? [/B] QUESTION: Is this the formula i need to use to solve this R=Vsquared/mew times g ? The answer I got is 62.018m. Am i doing this right?
correct

3) A pail of water is rotated in a vertical circle of radius 1m. What is the minimum speed of the pail at the top of the circle if no water is to spill out?
QUESTION: Is this the right formula Vsquared=RG? The answer I got is 3.03 m/s(squared) Am I on the the right track with this one?
At a glance your answer is the acceleration, but the question is asking for the speed.
 
in addition to previous comments:
1) coeff of friction generally given with (+) number. so here μk=+0.077
2) looks good. can you derive the formula which you stated?
3) basic formula is (mV2)/R = mg
so you're right that V2 = Rg
or V = √(Rg) = √(9.8) = 3.13 m/sec
 
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