What Happens to Primary Voltage if 8V is Applied to Secondary Coil?

AI Thread Summary
Applying 8V to the secondary coil of a transformer with a primary voltage of 120V and a secondary voltage of 6V results in a primary voltage of 160V. The relationship between the voltages is determined by the turns ratio, which remains constant. Using the formula v1/v2 = n1/n2, the calculation confirms that the primary voltage increases proportionally with the secondary voltage input. This scenario assumes the transformer operates ideally without losses. The conclusion is that the calculated primary voltage is accurate for an ideal transformer.
vroomba03
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Homework Statement


We have a transformer, the primary coil has 120V and secondary coil has 6V, if you put 8V in secondary coil, what will be the voltage in the primary coil.


Homework Equations


v1/v2 = n1/n2 where v is voltage and n is turns


The Attempt at a Solution


So i was thinking that the number of coils is going to be constant because there is no mention of them changing. So in that case the 120v/6v has to equal x/8v, which you would just solve for x, which comes out to 160v. That seemed kind of simple, so I wasnt sure i was doing that right. Any thoughts?
 
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vroomba03 said:

Homework Statement


We have a transformer, the primary coil has 120V and secondary coil has 6V, if you put 8V in secondary coil, what will be the voltage in the primary coil.


Homework Equations


v1/v2 = n1/n2 where v is voltage and n is turns


The Attempt at a Solution


So i was thinking that the number of coils is going to be constant because there is no mention of them changing. So in that case the 120v/6v has to equal x/8v, which you would just solve for x, which comes out to 160v. That seemed kind of simple, so I wasnt sure i was doing that right. Any thoughts?

Yup, it's as simple as that for ideal transformers.
 
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