What Image Forms with an Object Two Focal Lengths from a Diverging Lens?

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When an object is placed two focal lengths from a diverging lens, a virtual image is formed. The magnification of this image is 1, indicating that the image size is the same as the object size. The image is located on the same side of the lens as the object, specifically at a distance of -2f. The discussion highlights the need to use the Thin Lens formula instead of the Lens Maker's formula for accurate calculations. Understanding these principles is crucial for solving problems related to lens optics.
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Homework Statement



2. An object is placed two focal lengths from a
diverging lens.
What type of image forms?
What is the magnification?
Where is the image?

Homework Equations



1/f = (n-1)(1/r1-1/r2)

The Attempt at a Solution



a) Virtual Image

b) m = 1

c) the image is on the same side as the object with d_i = -2f
 
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sapiental said:

Homework Equations



1/f = (n-1)(1/r1-1/r2)
That's the "Lens Maker's formula"; what you need is the "Thin Lens formula". (Look it up!)
 
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