Don't go around trying to find the anti-derivative of that in elementary functions, the indefinite integral evaluates to Ei (m \ln x) + C, \frac{d}{dx}C = 0 where Ei(x) is the exponential integral. This result follows because after the substitution u= ln x, the original integral becomes \int^0_{-\infty} \frac{ (e^u)^m}{u} du.
Best you can do is to get an infinite series solution.
Well I might as well give another clue, try looking at H(-1) to evaluate the constant. If my mind was a bit clear yesterday, I could have told you that; looking at the natural logs series between 0 and 1, that integral is...