What is DC offset in an amplifier and how can it be eliminated?

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DC offset in an amplifier refers to a deviation from 0V, resulting in a shift of the waveform's mean voltage, which can be visually represented on an oscilloscope. This offset can manifest as a voltage level above or below zero, affecting signal integrity. To eliminate DC offset, capacitors are commonly used as filters since they block DC while allowing AC signals to pass, effectively removing the offset voltage. This method results in a cleaner waveform, essential for accurate signal processing. Understanding and addressing DC offset is crucial for optimal amplifier performance.
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Homework Statement


Explain what is meant by "DC Offset" in an amplifier and how can you eliminate it ?


2. The attempt at a solution
I think it is the deviation from the real voltage, but I am not sure
 
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DC Offset is pretty much what the name suggests - there is an offset from 0V (DC, I assume) to some other voltage, say, 4V. I guess the best way to explain it is when you look at a scope diagram. For example, say you're looking at a waveform that looks like http://www.innovatia.com/Design_Center/DC_images/image707.gif . The mean of the waveform (the dotted line) is above 0, and that height in the Y-axis is the offset.

I remember dealing with this in my engineering lab. I think we used a capacitor to act as a filter to get rid of the DC offset. The reason that I think a capacitor works is that a capacitor is an open circuit to DC, so none of that offset voltage passes through it, giving you a "clean" waveform.

http://www.innovatia.com/Design_Center/Electric_Circuits.htm
 
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