What is the Acceleration and Force of a Crate Being Pulled Across Ice?

AI Thread Summary
A 50-kg crate is pulled across ice with an 80 N force at a 36° angle, resulting in a vertical force of 443 N and a horizontal force of 64.72 N. The acceleration of the crate is calculated using F=ma, yielding an acceleration of approximately 1.29 m/s². The discussion clarifies that acceleration is determined by the horizontal force when the crate remains in constant contact with the ice. It emphasizes that the approach may vary depending on the specific scenario. Understanding the forces acting on the crate is crucial for accurate calculations.
halo9909
Messages
37
Reaction score
0

Homework Statement



A 50-kg crate is pulled across the ice with a rope. A force of 80 N is applied at an angle of 36° with the horizontal. Neglecting friction, calculate

(a) the acceleration of the crate.
m/s2
(b) the upward force the ice exerts on the crate as it is pulled.


Homework Equations



F=Ma
law of Cosines
law of sines

The Attempt at a Solution



I have the upward force "Fay" which is 443N
using the law of sines 80sin36 = 443N which is the vertical force and usig the law of cosines the horizontal is 64.72N

I am not sure how to calculate the acceleration
 
Physics news on Phys.org
Use F=ma. What is the force acting on the crate in the horizontal direction? That is the force that is causing the crate to accelerate.
 
oh wow thanks
so you use the "horizontal" force and with F=ma
the horizontal force of 64.72=50kg *a
it becomes 1.2944m/s

So you would always use the horizontal force to the ground for accleration or only in this case?
 
Since the crate is only moving in the horizontal direction (so it isn't rising falling - it stays in constant contact with the ice) the acceleration is only in the horizontal direction. I wouldn't say you always use the horizontal force, it depends on the situation.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

Work done by the force of a man on a crate of 80N
Replies
14
Views
6K
What is the largest pulling force before the string breaks?
Replies
13
Views
5K
What is the acceleration of the upper crate when the top crate begins to slide?
Replies
10
Views
4K
What is the acceleration of the crate?
Replies
12
Views
6K
How Much Force to Slide a Crate with Friction?
Replies
10
Views
2K
Friction Problem of a Crate Sliding Down a Ramp
Replies
4
Views
3K
What is the Change in Kinetic Energy of a Crate Being Pulled at an Angle?
Replies
1
Views
2K
Finding the force to pull a block up a frictionless slope?
Replies
12
Views
2K
Bead on a rod which is being pulled by an ideal string with velocity v
Replies
27
Views
995
What is the normal force exerted on a suitcase being pulled at an angle?
Replies
2
Views
2K

Hot Threads

Recent Insights

Back
Top