What is the acceleration due to gravity on this asteroid?

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Homework Help Overview

The problem involves determining the acceleration due to gravity on an asteroid based on the weight of an astronaut's pack in different gravitational fields. The context includes the astronaut's pack weighing 15.3 N on Earth and 3.05 N on the asteroid.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between force, mass, and acceleration using the equation F=ma. Questions arise regarding the correct interpretation of weight and mass, as well as the values needed to solve for acceleration.

Discussion Status

The discussion is active, with participants clarifying concepts related to force and mass. Some have attempted to set up a proportional relationship to find the acceleration, while others are addressing misunderstandings about units. No consensus has been reached, but there are indications of productive exploration of the problem.

Contextual Notes

There is a noted confusion regarding the distinction between force (in Newtons) and mass (in kilograms), which is affecting the participants' approaches to the problem. The original poster expresses uncertainty about the values needed for calculations.

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Homework Statement


An astronaut's pack weighs 15.3 N when she is on Earth but only 3.05 N when she is at the surface of an asteroid.

a. What is the acceleration due to gravity on this asteroid?

B. what is the mass of the pack on the asteroid?


Homework Equations


ok, I know I have to you F=ma; but I am stuck after that. I know my mass which is 3.05 N but what is my force?


The Attempt at a Solution



I tried, but i have two unknowns, I do not what the force is or what the acceleration which is what I am trying to calculate. I know I am missing something or I am overlooking something. Please help if you can. Thanks
 
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I know my mass which is 3.05 N but what is my force?

You have it mixed up. Force is measured in Newtons, while mass is measured in Kilograms.

You are right in saying that you have to use F = ma. What is the value of 'a' on the surface of the (perfectly spherical) Earth?
 
Well you could do it like this: [tex]\frac{15.3}{3.05} = \frac{9.8}{x}[/tex] I just rounded everything off and found that [tex]x = 1.95[/tex]
 
Last edited:
thank you so much. Yeah, I was mixed up about the mass and force units. So thanks.
 

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