What is the acceleration of a block on an inclined plane with friction?

  • Thread starter Thread starter Gilded
  • Start date Start date
  • Tags Tags
    Friction Plane
AI Thread Summary
The discussion focuses on calculating the acceleration of an 8 kg block on a 35-degree inclined plane with a 20 N applied force and a coefficient of kinetic friction of 0.3. Participants emphasize the importance of drawing a free body diagram to identify all forces acting on the block, including gravitational force, normal force, applied force, and friction. The net force acting on the block must be calculated by considering the direction of these forces, particularly noting that the block slides down the plane despite the applied force. The correct approach involves using Newton's laws and solving for the normal force first before determining the acceleration. Overall, a clear understanding of the forces and proper algebra is essential for finding the solution.
Gilded
Messages
3
Reaction score
0

Homework Statement


phsics.jpg

I have the weight of a mass (8KG) on a inclined plane(35 degrees) with an applied force going parallel to the plane at 20 N with a µK of .3

looking for acceleration

Homework Equations


(8*9.8*(sin(35)-20)/8)

The Attempt at a Solution


I got an answer of 200.2 using (8*9.8*(sin(35)-20)/8)

I'm looking for any equations related to this without the applied force also or if this is wrong the correct formula
 
Last edited:
Physics news on Phys.org
Gilded said:

Homework Statement


phsics.jpg

I have the weight of a mass (8KG) on a inclined plane(35 degrees) with an applied force going parallel to the plane at 20 N with a MuK of .3


Homework Equations


(8*9.8*(sin(35)-20)/8)


The Attempt at a Solution


I got an answer of 200.2 using (8*9.8*(sin(35)-20)/8)

I'm looking for any equations related to this without the applied force also or if this is wrong the correct formula
I assume the 20 N applied force is pointing up the plane? Are you trying to find the acceleration? Which way does the block slide, up or down? What happened to the friction force? Draw a free body diagram to identify all the forces acting (weight, normal force, friction force, applied force) , then use Newton's laws.
 
the friction is .3, it slides up the ramp, I should have drawn that picture better.
 
How can it slide up with a 20 N applied load if gravity alone is pulling it down with a force of mgsintheta = 45 N or so??
 
I was taking a stab at the dark with the direction. I'm really bad at this and i haven't been able to find any useful formula on the internet or none seemed useful.
 
Gilded said:
I was taking a stab at the dark with the direction. I'm really bad at this and i haven't been able to find any useful formula on the internet or none seemed useful.
Well, I'll catch you a bit later, the block slides down the plane, and you must draw a free body diagram. You have 20N up the plane, 45N down the plane from gravity, and (mu)N from the friction force, acting up the plane, opposing the motion of the block. Add them up with appropriate plus/minus signs and set them equal to 'ma' to solve for a, but first solve for N, the normal force. Also, watch your algebra. Can you calculate the normal force which acts up on the block, perpendicular to the plane? And by the way, welcome to PF!
 
Last edited:
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top