How Does a Ship's Angle and Friction Affect Its Acceleration Down a Ramp?

Thread starter HaZzArD 09
Start date Nov 23, 2009
Tags

Acceleration

AI Thread Summary

The discussion centers on calculating the acceleration of a ship launched down an 8-degree ramp with a coefficient of kinetic friction of 0.06. Participants are exploring the relevant formulas, including the forces acting on the ship, such as gravitational force and friction. The equations discussed include f=mg sin(θ) for the force due to gravity and N=mg cos(θ) for the normal force. The net force equation, Fx=max=Fgx + f, is also mentioned to find acceleration. Understanding these relationships is crucial for determining the ship's acceleration down the ramp.

Nov 23, 2009

HaZzArD 09

A ship is launched into the water down a ramp making an angle of 8 degrees with the horizontal. The Coefficient of kinetic friction between the boat and the ramp is Mk = 0.06. What is the acceleration?

Physics news on Phys.org

Nov 23, 2009

diazona

Homework Helper

What have you tried?

Nov 23, 2009

HaZzArD 09

I'm not sure which formula to use.
There's f=mg sin0=MsN
N=mg cos0
Fx=max=Fgx +f
max= mg sin0 - Mmg cos0
Mk=Fkx/N

Thread 'I've come across another fluid pressure problem I don't understand'

Neglect gravity other than that of water; neglect friction. F1=ρgsh=1000*10*1*(1+4)=50000 N; F1=ρgsh=1000*10*0.1*4=4000 N; F3=50000-4000=46000 N?

View full post »

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

View full post »

Thread 'Understanding Forces and their Vector Components'

I was told forces are vectors so they can be divided into x and y components, but what about the normal force or the force of static friction? do you divide those into x and y components if say you had a block that was lying on an angled surface?

View full post »