What is the acceptance of the detector?

tsinghua
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dear all

is there anybody familiar with the definition of the acceptance of detector, especially used in high energy physics? please explain it for me.

Thanks in advance!
 
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If you have two 10-cm diameter scintillators for cosmic rays 1 meter apart, the aperture at zero degrees incidence is about 79 cm2. Also, the maximum detectable angle of incidence is about 0.1 radians (0.01 steradians), but with an elffective aperture of nearly 0 cm2. The most accurate statement of acceptance is an integration of the aperture over the solid angle, giving an answer in cm2-steradians.
 
In particle accelerators, you usually know where the particles collide. The products of these events can now fly in every direction, but you usually cannot (or do not want) detect all products due to mechanical or cost limitations. The region where the particles can be detected is the acceptance. Sometimes the detection depends on the energy of the particles, too - in this case, your acceptance is not just a function of the direction, but of direction and energy of the particle.
 
Thank Bob S and mfb so much. Now I understand it.
best,
tsinghua
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...

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