What is the average power being expended?

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Homework Statement


A person is making homemade ice cream. She exerts a force of magnitude 19 N on the free end of the crank handle, and this end moves in a circular path of radius 0.28 m. The force is always applied parallel to the motion of the handle. If the handle is turned once every 1.7 s, what is the average power being expended?


Homework Equations


W=FD cos theta
P=W/T


The Attempt at a Solution


I first found the work by using W =FD cos theta. The force is 19, the distance traveled is .28*2*pi, so I got that the work is 33.427. I then divided by T, 1.7 to get P, which is 19.663 W. What did I do wrong?
 
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What did I do wrong?
 


keemosabi said:
What did I do wrong?

What makes you think you did anything wrong? That looks fine to me.
 

Thread 'Prove that the integral is equal to ##\pi^2/8##'

Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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