What is the Capacitance of a Capacitor with Two Different Dielectrics?

[DrunkApple]

Homework Statement

A capacitor is constructed from two square
metal plates. A dielectric \kappa = 4.61 fills the
upper half of the capacitor and a dielectric
\kappa = 6.9 fills the lower half of the capacitor.
Neglect edge effects. Calculate the capacitance C of the device.
Answer in units of pF

Homework Equations

C_{TOP} = \kappa\epsilonA/d
C_{bottom} = \kappa\epsilonA/d
C_{total} = C_{TOP} + C_{BOTTOM}

The Attempt at a Solution

C_{TOP} = \kappa\epsilonA/d
= 4.61(8.85419*10^{-12})(.12^{2})/0.0005
= 1.175553098*10^{-9}
C_{bottom} = 6.9(8.85419*10^{-12})(.12^{2})/0.0005
= 1.759504637*10^{-9}
C_{total} = 2.935057735*10^{-9}
Is this correct?

 

[gneill]

Homework Statement

A capacitor is constructed from two square
metal plates. A dielectric \kappa = 4.61 fills the
upper half of the capacitor and a dielectric
\kappa = 6.9 fills the lower half of the capacitor.
Neglect edge effects. Calculate the capacitance C of the device.
Answer in units of pF

Ummm. Plate size? Plate separation? Are the plates oriented vertically or horizontally?