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DrunkApple
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Homework Statement
A capacitor is constructed from two square
metal plates. A dielectric [itex]\kappa[/itex] = 4.61 fills the
upper half of the capacitor and a dielectric
[itex]\kappa[/itex] = 6.9 fills the lower half of the capacitor.
Neglect edge effects. Calculate the capacitance C of the device.
Answer in units of pF
Homework Equations
C[itex]_{TOP}[/itex] = [itex]\kappa[/itex][itex]\epsilon[/itex]A/d
C[itex]_{bottom}[/itex] = [itex]\kappa[/itex][itex]\epsilon[/itex]A/d
C[itex]_{total}[/itex] = C[itex]_{TOP}[/itex] + C[itex]_{BOTTOM}[/itex]
The Attempt at a Solution
C[itex]_{TOP}[/itex] = [itex]\kappa[/itex][itex]\epsilon[/itex]A/d
= 4.61(8.85419*10[itex]^{-12}[/itex])(.12[itex]^{2}[/itex])/0.0005
= 1.175553098*10[itex]^{-9}[/itex]
C[itex]_{bottom}[/itex] = 6.9(8.85419*10[itex]^{-12}[/itex])(.12[itex]^{2}[/itex])/0.0005
= 1.759504637*10[itex]^{-9}[/itex]
C[itex]_{total}[/itex] = 2.935057735*10[itex]^{-9}[/itex]
Is this correct?