- #1
BriannaUND
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I am having problems with the following questions. Any help would be greatly appreciated!
19) Automobile travels at constant speed of 60 km/hr (16.7m/s), 800 m along a straight highway that is inclined 5 degrees to the horizontal. An observer notes only the vertical motion of hte car. What is the car's vertical velocity and vertical travel distance.
Part A: vy= vsin5= 16.7 x sin5 = 1.46 m/s
Part B: I don't know which equation to use because the problem doesn't state a given amount of time. I don't know how to figure out the time from this but I'm assuming once I get that number I can put it into the equation
y= (vsin5)t
80)A pitcher throws a fastball horizontally at a speed of 140 km/hr (38.9m/s) toward home plate, 18.4 m away. a) If the batter's combined reaction and swing times total .350sec, how long can the batter watch the ball after it has left the pitchers hand before swinging? b) In traveling to the plate, how far does the ball drop from its original horizontal line?
Part A: I calculated 38.9 m/s divided by 18.4 m to get 2.11 sec or the time it takes for the ball to reach home plate from the pitcher. I then subtracted 2.11 sec- .350 sec = 1.76 sec for the time the batter can watch.
Part B: I tried substituting my numbers into the equation x=vxt = 38.9 m/s x 1.76 sec = 68.5 m but I don't think that this number looks accurate.
19) Automobile travels at constant speed of 60 km/hr (16.7m/s), 800 m along a straight highway that is inclined 5 degrees to the horizontal. An observer notes only the vertical motion of hte car. What is the car's vertical velocity and vertical travel distance.
Part A: vy= vsin5= 16.7 x sin5 = 1.46 m/s
Part B: I don't know which equation to use because the problem doesn't state a given amount of time. I don't know how to figure out the time from this but I'm assuming once I get that number I can put it into the equation
y= (vsin5)t
80)A pitcher throws a fastball horizontally at a speed of 140 km/hr (38.9m/s) toward home plate, 18.4 m away. a) If the batter's combined reaction and swing times total .350sec, how long can the batter watch the ball after it has left the pitchers hand before swinging? b) In traveling to the plate, how far does the ball drop from its original horizontal line?
Part A: I calculated 38.9 m/s divided by 18.4 m to get 2.11 sec or the time it takes for the ball to reach home plate from the pitcher. I then subtracted 2.11 sec- .350 sec = 1.76 sec for the time the batter can watch.
Part B: I tried substituting my numbers into the equation x=vxt = 38.9 m/s x 1.76 sec = 68.5 m but I don't think that this number looks accurate.