What is the Cartesian form of 1/(2^j)?

[chonghuh]

Homework Statement

I solved this following problem but I am not sure whether I did this right: convert
(1/(2^j)) to cartesian form.

Homework Equations

The Attempt at a Solution

re^j\theta = a+jb

a=r cos \theta= cos -\pi/2
b= sin -\pi/2 = -1

1/(2^j) = 2^-j
=2^e^(-pi j /2)
=2^-j

 

[Dick]

1/2^j=2^(-j) as you said. But to get to the e form use 2=e^ln(2).